m^2-25/3m+15/5-m/3

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Solution for m^2-25/3m+15/5-m/3 equation: 


m in (-oo:+oo)

m^2-((25/3)*m)-(m/3)+15/5 = 0

m^2+(-25/3)*m-(m/3)+15/5 = 0

m^2-26/3*m+3 = 0

DELTA = (-26/3)^2-(1*3*4)

DELTA = 568/9

DELTA > 0

m = ((568/9)^(1/2)+26/3)/(1*2) or m = (26/3-(568/9)^(1/2))/(1*2)

m = ((568/9)^(1/2)+26/3)/2 or m = (26/3-(568/9)^(1/2))/2

m in { (26/3-(568/9)^(1/2))/2, ((568/9)^(1/2)+26/3)/2 }

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